Optimal. Leaf size=150 \[ \frac{5 a^4 (A+2 B) \sin (c+d x)}{2 d}+\frac{a^4 (4 A+B) \tanh ^{-1}(\sin (c+d x))}{d}-\frac{(3 A-B) \sin (c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{3 d}-\frac{(3 A-8 B) \sin (c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{6 d}+\frac{1}{2} a^4 x (13 A+12 B)+\frac{a A \tan (c+d x) (a \cos (c+d x)+a)^3}{d} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.453221, antiderivative size = 150, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.194, Rules used = {2975, 2976, 2968, 3023, 2735, 3770} \[ \frac{5 a^4 (A+2 B) \sin (c+d x)}{2 d}+\frac{a^4 (4 A+B) \tanh ^{-1}(\sin (c+d x))}{d}-\frac{(3 A-B) \sin (c+d x) \left (a^2 \cos (c+d x)+a^2\right )^2}{3 d}-\frac{(3 A-8 B) \sin (c+d x) \left (a^4 \cos (c+d x)+a^4\right )}{6 d}+\frac{1}{2} a^4 x (13 A+12 B)+\frac{a A \tan (c+d x) (a \cos (c+d x)+a)^3}{d} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2975
Rule 2976
Rule 2968
Rule 3023
Rule 2735
Rule 3770
Rubi steps
\begin{align*} \int (a+a \cos (c+d x))^4 (A+B \cos (c+d x)) \sec ^2(c+d x) \, dx &=\frac{a A (a+a \cos (c+d x))^3 \tan (c+d x)}{d}+\int (a+a \cos (c+d x))^3 (a (4 A+B)-a (3 A-B) \cos (c+d x)) \sec (c+d x) \, dx\\ &=-\frac{(3 A-B) \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{3 d}+\frac{a A (a+a \cos (c+d x))^3 \tan (c+d x)}{d}+\frac{1}{3} \int (a+a \cos (c+d x))^2 \left (3 a^2 (4 A+B)-a^2 (3 A-8 B) \cos (c+d x)\right ) \sec (c+d x) \, dx\\ &=-\frac{(3 A-B) \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{3 d}-\frac{(3 A-8 B) \left (a^4+a^4 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac{a A (a+a \cos (c+d x))^3 \tan (c+d x)}{d}+\frac{1}{6} \int (a+a \cos (c+d x)) \left (6 a^3 (4 A+B)+15 a^3 (A+2 B) \cos (c+d x)\right ) \sec (c+d x) \, dx\\ &=-\frac{(3 A-B) \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{3 d}-\frac{(3 A-8 B) \left (a^4+a^4 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac{a A (a+a \cos (c+d x))^3 \tan (c+d x)}{d}+\frac{1}{6} \int \left (6 a^4 (4 A+B)+\left (6 a^4 (4 A+B)+15 a^4 (A+2 B)\right ) \cos (c+d x)+15 a^4 (A+2 B) \cos ^2(c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac{5 a^4 (A+2 B) \sin (c+d x)}{2 d}-\frac{(3 A-B) \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{3 d}-\frac{(3 A-8 B) \left (a^4+a^4 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac{a A (a+a \cos (c+d x))^3 \tan (c+d x)}{d}+\frac{1}{6} \int \left (6 a^4 (4 A+B)+3 a^4 (13 A+12 B) \cos (c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac{1}{2} a^4 (13 A+12 B) x+\frac{5 a^4 (A+2 B) \sin (c+d x)}{2 d}-\frac{(3 A-B) \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{3 d}-\frac{(3 A-8 B) \left (a^4+a^4 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac{a A (a+a \cos (c+d x))^3 \tan (c+d x)}{d}+\left (a^4 (4 A+B)\right ) \int \sec (c+d x) \, dx\\ &=\frac{1}{2} a^4 (13 A+12 B) x+\frac{a^4 (4 A+B) \tanh ^{-1}(\sin (c+d x))}{d}+\frac{5 a^4 (A+2 B) \sin (c+d x)}{2 d}-\frac{(3 A-B) \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{3 d}-\frac{(3 A-8 B) \left (a^4+a^4 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac{a A (a+a \cos (c+d x))^3 \tan (c+d x)}{d}\\ \end{align*}
Mathematica [B] time = 1.54755, size = 312, normalized size = 2.08 \[ \frac{1}{192} a^4 (\cos (c+d x)+1)^4 \sec ^8\left (\frac{1}{2} (c+d x)\right ) \left (\frac{3 (16 A+27 B) \sin (c) \cos (d x)}{d}+\frac{3 (A+4 B) \sin (2 c) \cos (2 d x)}{d}+\frac{3 (16 A+27 B) \cos (c) \sin (d x)}{d}+\frac{3 (A+4 B) \cos (2 c) \sin (2 d x)}{d}-\frac{12 (4 A+B) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )}{d}+\frac{12 (4 A+B) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}{d}+\frac{12 A \sin \left (\frac{d x}{2}\right )}{d \left (\cos \left (\frac{c}{2}\right )-\sin \left (\frac{c}{2}\right )\right ) \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )}+\frac{12 A \sin \left (\frac{d x}{2}\right )}{d \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}+78 A x+\frac{B \sin (3 c) \cos (3 d x)}{d}+\frac{B \cos (3 c) \sin (3 d x)}{d}+72 B x\right ) \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.148, size = 190, normalized size = 1.3 \begin{align*}{\frac{A{a}^{4}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2\,d}}+{\frac{13\,A{a}^{4}x}{2}}+{\frac{13\,A{a}^{4}c}{2\,d}}+{\frac{B\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{2}{a}^{4}}{3\,d}}+{\frac{20\,{a}^{4}B\sin \left ( dx+c \right ) }{3\,d}}+4\,{\frac{A{a}^{4}\sin \left ( dx+c \right ) }{d}}+2\,{\frac{{a}^{4}B\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{d}}+6\,{a}^{4}Bx+6\,{\frac{{a}^{4}Bc}{d}}+4\,{\frac{A{a}^{4}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+{\frac{A{a}^{4}\tan \left ( dx+c \right ) }{d}}+{\frac{{a}^{4}B\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [A] time = 1.01106, size = 252, normalized size = 1.68 \begin{align*} \frac{3 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{4} + 72 \,{\left (d x + c\right )} A a^{4} - 4 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B a^{4} + 12 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{4} + 48 \,{\left (d x + c\right )} B a^{4} + 24 \, A a^{4}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 6 \, B a^{4}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 48 \, A a^{4} \sin \left (d x + c\right ) + 72 \, B a^{4} \sin \left (d x + c\right ) + 12 \, A a^{4} \tan \left (d x + c\right )}{12 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A] time = 1.67625, size = 383, normalized size = 2.55 \begin{align*} \frac{3 \,{\left (13 \, A + 12 \, B\right )} a^{4} d x \cos \left (d x + c\right ) + 3 \,{\left (4 \, A + B\right )} a^{4} \cos \left (d x + c\right ) \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \,{\left (4 \, A + B\right )} a^{4} \cos \left (d x + c\right ) \log \left (-\sin \left (d x + c\right ) + 1\right ) +{\left (2 \, B a^{4} \cos \left (d x + c\right )^{3} + 3 \,{\left (A + 4 \, B\right )} a^{4} \cos \left (d x + c\right )^{2} + 8 \,{\left (3 \, A + 5 \, B\right )} a^{4} \cos \left (d x + c\right ) + 6 \, A a^{4}\right )} \sin \left (d x + c\right )}{6 \, d \cos \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A] time = 1.34447, size = 305, normalized size = 2.03 \begin{align*} -\frac{\frac{12 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1} - 3 \,{\left (13 \, A a^{4} + 12 \, B a^{4}\right )}{\left (d x + c\right )} - 6 \,{\left (4 \, A a^{4} + B a^{4}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) + 6 \,{\left (4 \, A a^{4} + B a^{4}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (21 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 30 \, B a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 48 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 76 \, B a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 27 \, A a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 54 \, B a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{3}}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]